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A mathematical problem suggested by Gurgen Asatryan, a lecturer of the Chair of Mathematics and its Teaching Methods, has been included in the 59th International Mathematics Olympiad.
This is the second time a problem suggested by Armenian specialists has been included in the six-problem mathematical Olympiad after 22 years’ break.
Every year about 200 problems are submitted to the Problem Selection Committee which reduces the submitted problems to a shortlist. The IMO Jury is responsible for all the formal decisions relating to the contest, starting with selecting the six problems from the shortlist.
Talking to www.old.aspu.am, Gurgen Asatryan said many of the mathematical problems he authored have been included in Republican Olympiads. This is the first time a mathematical problem he suggested has been included in the International Mathematics Olympiad.
“I submitted two problems; one of them was selected. It is a great honour for me as the selection is made by leading specialists,” he said. Gurgen Asatryan added that Armenia was represented by six participants who won two silver and four bronze medals.
Below is the mathematical problem (IMO Problem 4) authored by Gurgen Asatryan.
Problem 4. A site is any point in the plane such that and are both positive integers less than or equal to 20. Initially, each of the 400 sites is unoccupied. Amy and Ben take turns placing stones with Amy going first. On her turn, Amy places a new red stone on an unoccupied site such that the distance between any two sites occupied by red stones is not equal to . On his turn, Ben places a new blue stone on any unoccupied site. (A site occupied by a blue stone is allowed to be at any distance from any other occupied site.) They stop as soon as a player cannot place a stone. Find the greatest such that Amy can ensure that she places at least red stones, no matter how Ben places his blue stones.
